#include<iostream>
using namespace std;
#include<conio.h>
int main()
{
float a,b,c,d,e,t,a2,b2,c2,d2,e2,s;
int a1,b1,c1,d1,e1;
cout<<"\nInput a 5 digit number";
cin>>t;
a=t/10000.0;
a1=a;
b=(t-(a1*10000.0))/1000;
b1=b;
c=(t-(a1*10000.0)-(b1*1000))/100;
c1=c;
d=(t-(a1*10000.0)-(b1*1000)-(c1*100))/10;
d1=d;
e=t-(a1*10000.0)-(b1*1000)-(c1*100)-(d1*10);
e1=e;
a2=e1*10000.0;
b2=d1*1000.0;
c2=c1*100.0;
d2=b1*10.0;
e2=a1*1.0;
s=a2+b2+c2+d2+e2;
cout<<"\nThe required result is "<<s;
getch();
return 0;
Understandable C and C++ programming tutorials, compiler reviews, source code, tips and tricks.
*/
}
using namespace std;
#include<conio.h>
int main()
{
float a,b,c,d,e,t,a2,b2,c2,d2,e2,s;
int a1,b1,c1,d1,e1;
cout<<"\nInput a 5 digit number";
cin>>t;
a=t/10000.0;
a1=a;
b=(t-(a1*10000.0))/1000;
b1=b;
c=(t-(a1*10000.0)-(b1*1000))/100;
c1=c;
d=(t-(a1*10000.0)-(b1*1000)-(c1*100))/10;
d1=d;
e=t-(a1*10000.0)-(b1*1000)-(c1*100)-(d1*10);
e1=e;
a2=e1*10000.0;
b2=d1*1000.0;
c2=c1*100.0;
d2=b1*10.0;
e2=a1*1.0;
s=a2+b2+c2+d2+e2;
cout<<"\nThe required result is "<<s;
getch();
return 0;
/* Letuswithc:
this page is designed to help you learn C or C++.Understandable C and C++ programming tutorials, compiler reviews, source code, tips and tricks.
*/
}
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